Permittivity is 0.8 s⁻¹, head difference is 0.05 m and test area is 0.20 m². For a normal-flow test using Q = ψΔhA, what flow results?
A 0.080 m³/s
B 0.008 m³/s
C 0.010 m³/s
D 0.004 m³/s
Answer: B. 0.008 m³/s. Multiply 0.8 by 0.05 and 0.20 to obtain 0.008 m³/s.
Media efficiency is 99% for particles traversing it, but 4% of equal-concentration inlet flow bypasses the filter. What is system efficiency?
A 99.00%
B 96.00%
C 94.00%
D 95.04%
Answer: D. 95.04%. Only 96% of the inlet flow passes through the medium. Multiply 0.96 × 0.99.
A unidirectional composite is loaded parallel to fibres. Let both phases have equal strain. Fibres are 50% by volume and have modulus 150 GPa, while matrix modulus is 3 GPa. Approximately what share of axial force is carried by fibres?
A 50.0%
B 75.0%
C 98.0%
D 2.0%
Answer: C. 98.0%. At equal strain, the force share is proportional to modulus times area fraction. For equal fractions, the fibre share is 150/(150 + 3).
Across an assembly with area-specific thermal resistance 0.25 m²·K/W, temperature drops by 15 K. What steady heat flux does the simple model predict?
A 3.75 W/m²
B 25 W/m²
C 0.0167 W/m²
D 60 W/m²
Answer: D. 60 W/m². Heat flux in this model equals temperature difference divided by area-specific resistance.
Using Q = θiw, find in-plane flow through a 4 m wide sheet with transmissivity 0.003 m²/s and gradient 0.5.
A 0.024 m³/s
B 0.0015 m³/s
C 0.006 m³/s
D 0.000375 m³/s
Answer: C. 0.006 m³/s. The product is 0.003 × 0.5 × 4 = 0.006 m³/s.
In a hygiene test, 30 g of dry core retains 210 g of liquid. How much liquid is retained per gram of dry core?
A 7 g/g
B 8 g/g
C 6 g/g
D 0.143 g/g
Answer: A. 7 g/g. Divide 210 g of retained liquid by 30 g of dry core.
Fibre mass is 180 g at density 1.8 g/cm³ and resin mass is 120 g at density 1.2 g/cm³. With no voids, what is fibre volume fraction?
A 40%
B 50%
C 60%
D 75%
Answer: B. 50%. Each constituent occupies 100 cm³, so fibres account for half the composite volume.
Two identical filter panels operate in parallel. At the same combined airflow as one panel, each panel carries half the flow. If pressure drop is linear in flow, how does overall pressure drop compare with one panel?
A It halves
B It doubles
C It stays unchanged
D It is a quarter
Answer: A. It halves. Each branch sees the same overall pressure drop. Each carries half the former flow, requiring half the pressure in the assumed linear regime.
Radiation transmission through two layers is 20% and 10% of what reaches each one, with no interaction in a simple independent model. What overall fraction is transmitted?
A 2%
B 30%
C 20%
D 10%
Answer: A. 2%. Multiply the two transmission fractions: 0.20 × 0.10 = 0.02.
A protective laminate passes a flat sample test but leaks after flexing along a seam. Which experimental comparison most directly checks the proposed failure location?
A Measure yarn shade under light
B Compare seam and flat regions
C Use only overall roll mass
D Retest only pristine flat samples
Answer: B. Compare seam and flat regions. Matched tests on zones with and without the seam show whether flex-induced leakage is concentrated in the seam region.
Mass gain of a moisture barrier sample is 18 g in 3 h through 0.03 m². Assuming constant rate, how much mass transfers per square metre per hour?
A 20 g/(m²·h)
B 200 g/(m²·h)
C 2 g/(m²·h)
D 600 g/(m²·h)
Answer: B. 200 g/(m²·h). The hourly mass transfer is 6 g. Divide it by 0.03 m².
Under higher confinement, in-plane flow drops from 1.2 to 0.75 L/s at the same gradient. What percentage of original flow remains?
A 62.5%
B 37.5%
C 75.0%
D 60.0%
Answer: A. 62.5%. Divide the confined flow by the original flow: 0.75/1.2 = 0.625.
Assume ideal continuous aligned fibres at 60% volume, fibre modulus 200 GPa and matrix modulus 4 GPa. By the longitudinal rule of mixtures, what modulus is predicted?
A 204.0 GPa
B 81.6 GPa
C 121.6 GPa
D 120.0 GPa
Answer: C. 121.6 GPa. The volume-weighted sum is 0.60 × 200 plus 0.40 × 4, or 121.6 GPa.
What power is dissipated in a constant 12 Ω textile heating track with 6 V across it?
A 3 W
B 0.5 W
C 6 W
D 72 W
Answer: A. 3 W. Power is V²/R, so 36/12 = 3 W.
Two textile sheets are stacked in a normal-flow test. Each sheet alone would have the same head loss at a given flow. If their head losses add and the total head stays fixed, how does the stack flow compare with one sheet in the linear model?
A It is twice as large
B It is half as large
C It is four times larger
D It remains the same
Answer: B. It is half as large. Two identical linear hydraulic resistances in series need twice the head at the same flow. At fixed total head, the flow halves.
First filter stage removes 80% of incoming particles and the second removes 90% of particles reaching it. What overall efficiency results with no bypass?
A 90%
B 72%
C 98%
D 85%
Answer: C. 98%. Remaining fractions multiply: 0.20 × 0.10 = 0.02. The collection efficiency is 98%.
Stretch increases film area by 25% and film volume is conserved. For a uniform layer, what is the new thickness relative to the old?
A 125%
B 80%
C 100%
D 75%
Answer: B. 80%. Volume equals area multiplied by thickness. The thickness ratio is 1/1.25 = 0.80.
At 0.50 m³/s flow and 240 Pa pressure drop, what fluid power is needed to drive air through a filter, ignoring motor losses?
A 480 W
B 240 W
C 120 W
D 12 W
Answer: C. 120 W. Fluid power is volumetric flow × pressure difference. The result is 0.50 × 240 = 120 W.
With 55% fibre by volume and no voids, what composite density follows from fibre and matrix densities of 1.8 and 1.2 g/cm³?
A 1.40 g/cm³
B 1.50 g/cm³
C 1.65 g/cm³
D 1.53 g/cm³
Answer: D. 1.53 g/cm³. Multiply the constituent densities by their volume fractions and add: 0.55 × 1.8 + 0.45 × 1.2.
Two identical 12 Ω conductive textile paths connect the same two points in parallel. What equivalent resistance results?
A 24 Ω
B 3 Ω
C 6 Ω
D 12 Ω
Answer: C. 6 Ω. Two equal resistances in parallel give half the resistance of either path.
Across a textile 4 mm thick, hydraulic conductivity is 0.002 m/s. Under ψ = k/t, what is permittivity?
A 0.50 s⁻¹
B 0.005 s⁻¹
C 8.00 s⁻¹
D 2.00 s⁻¹
Answer: A. 0.50 s⁻¹. Convert 4 mm to 0.004 m. Divide 0.002 m/s by 0.004 m.
One medium clogs sooner than another at matched airflow and dust loading, although initial particle collection is equal. Which performance curve distinguishes the media?
A Textile width versus humidity
B Shade versus yarn twist
C Fibre length versus colour
D Pressure drop versus dust loading
Answer: D. Pressure drop versus dust loading. Tracking pressure drop as dust accumulates shows how quickly resistance rises during loading.
What thickness follows from a uniform panel’s areal mass of 1.2 kg/m² and bulk density of 1,500 kg/m³?
A 0.08 mm
B 0.80 mm
C 8.00 mm
D 1.25 mm
Answer: B. 0.80 mm. Thickness equals areal mass divided by density: 1.2/1,500 m = 0.0008 m.
For a 6 mm insulator with conductivity 0.04 W/(m·K), calculate thermal resistance per unit area in the plane-layer model.
A 6.67 m²·K/W
B 0.24 m²·K/W
C 0.015 m²·K/W
D 0.15 m²·K/W
Answer: D. 0.15 m²·K/W. Divide thickness in metres by conductivity, 0.006/0.04 = 0.15 m²·K/W.
At constant volumetric flow, exposed filter area increases by 50%. What is the new face velocity as a fraction of the old?
A One half
B Three halves
C One third
D Two thirds
Answer: D. Two thirds. Velocity is flow divided by area, so its ratio is 1/1.5.