# Line slope calculator 2x+5y=19

**Straight line given by points A[2; 3] and B[7; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+3.8

**Canonical form of the line equation:**2x+5y-19 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -2t+3 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 9.5

**Y intercept:**y

_{0}= q = 3.8

**Distance line from the origin:**d

_{0}= 3.5282

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[4.5; 2]

**Perpendicular Bisector equation:**5x-2y-18.5 = 0

**Vector OA = (2; 3) ; |OA| = 3.6056**

**Vector OB = (7; 1) ; |OB| = 7.0711**

**Scalar product OA .OB = 17**

**Angle ∠ AOB = 48°10'47″ = 0.8409 rad**