Consider a style with work content of 14.4 standard minutes and target takt of 0.80 min/garment. Before precedence and equipment restrictions, what is the theoretical minimum operator count?
A 16
B 20
C 18
D 12
Answer: C. 18. Divide work content by takt time, then round up if needed. Here the result is exactly 18.
Usable roll length is 180 m. Each ply needs a 5.8 m marker plus 0.20 m end loss. With five garments per ply, how many garment sets can be cut?
A 150
B 180
C 145
D 155
Answer: A. 150. Each full ply consumes 6.0 m, so 30 plies fit. Multiply by five garments.
Two independent sewing sections have first-pass yields of 95% and 96%. Assuming garments must pass both without rework, what fraction passes first time?
A 91.2%
B 99.8%
C 96.0%
D 95.5%
Answer: A. 91.2%. Multiply the two stage yields: 0.95 × 0.96.
Three tasks take 19, 16 and 13 seconds at one station. If whole tasks can be reassigned and no precedence constraint applies, what is the smallest task that can be moved to meet the 44-second target?
A 16 s task
B No single task works
C 13 s task
D 19 s task
Answer: C. 13 s task. The total of 48 s exceeds target by 4 s. Removing the smallest entire task, 13 s, reduces total to 35 s.
Style A uses 40 minutes setup plus 1.8 min per unit. Style B uses 100 minutes setup plus 1.2 min per unit. At what batch size are total times equal?
A 50 units
B 200 units
C 60 units
D 100 units
Answer: D. 100 units. Solve 40 + 1.8n = 100 + 1.2n. The 60-minute setup difference is offset by 0.6 min per unit.
One operator can sew a seam in 0.9 min. To support 220 garments in a 110-minute activity window, how many identical parallel stations are needed?
A 2
B 3
C 4
D 1
Answer: A. 2. One station can supply about 122 garments. Two can support the required rate of 2 garments per minute.
Observed sewing time is 54 s at a performance rating of 110%. Allowance equals 10% of the final standard time. What is standard time?
A 60 s
B 65.34 s
C 59.4 s
D 66 s
Answer: D. 66 s. Normal time is 54 × 1.10 = 59.4 s. It is 90% of standard time, so divide by 0.90.
At steady flow, a sewing line completes 60 garments/h and carries 90 garments in process on average. Estimate mean flow time.
A 5.4 h
B 1.5 h
C 2.0 h
D 0.67 h
Answer: B. 1.5 h. Under Little’s law, mean flow time equals work in process divided by throughput, 90/60 h.
Start with 1,000 garments. First-pass yield is 92%. Of the failures, 75% can be successfully reworked. How many good garments result after rework?
A 920
B 1,000
C 965
D 980
Answer: D. 980. There are 920 first-pass successes and 0.75 × 80 = 60 recovered garments.
Two marker options contain the same garment pattern area. Marker B is 5% shorter at equal width. How does its efficiency compare to A?
A It is unchanged
B It is about 5.26% higher
C It is about 4.76% lower
D It is exactly 5% lower
Answer: B. It is about 5.26% higher. Efficiency is inversely proportional to marker area for the same piece area. The ratio is 1/0.95.
Fusing and sewing in sequence have capacities of 240 and 180 components/h. Every garment requires two components through both stages. What is the steady output limit for whole garments per hour?
A 210
B 180
C 120
D 90
Answer: D. 90. The downstream stage limits output to 180 components/h. Each garment consumes two components, yielding 90 garments/h.
For stations rated at 150, 120 and 130 garments/h, a second identical operator is added at the 120 garments/h station. Ignoring other constraints, what is the new maximum line output?
A 150 garments/h
B 130 garments/h
C 120 garments/h
D 240 garments/h
Answer: B. 130 garments/h. Parallel capacity raises that stage to 240 per hour. The 130 per hour stage becomes the constraint.
Demand is 450 garments per shift of 450 productive minutes. Before a change, actual cycle time is 75 s. How many garments per shift must be added to meet demand?
A 60
B 90
C 75
D 150
Answer: B. 90. Seventy-five seconds is 1.25 min, so output is 360 garments. Demand exceeds this by 90.
At a production run, five garment sizes must appear in the ratio 1:2:3:2:1. How many size-3 garments are in a complete batch of 360 at this ratio?
A 120
B 90
C 80
D 40
Answer: A. 120. The ratio has nine total parts, and size 3 uses three of them. Multiply 360 by 3/9.
During an eight-hour shift, a two-minute operation is active for 85% of the time. How many whole units can it finish?
A 170
B 240
C 408
D 204
Answer: D. 204. Available active minutes are 480 × 0.85 = 408. Divide by 2.0.
After washing, bond failure occurs only in the fused collar. Which trial isolates the effect of fusing?
A Switch both fabric and lining
B Compare only finished appearance
C Change only fusing parameters
D Change cutter and seam settings
Answer: C. Change only fusing parameters. Holding materials and other processes constant while varying fusing conditions tests their effect on postwash bond quality.
With 20 operators working 450 minutes each, 15 standard minutes per garment and 72% planning efficiency, what output is expected?
A 324
B 432
C 600
D 540
Answer: B. 432. Earned standard time is 20 × 450 × 0.72 = 6,480 min. Divide by 15.
Purchased cloth is 1.60 m wide, but 3 cm at each edge are unusable. Over a 10 m marker length, what area can be used?
A 16.0 m²
B 15.7 m²
C 15.4 m²
D 13.0 m²
Answer: C. 15.4 m². Remove 0.06 m from the width and multiply the remaining 1.54 m by 10 m.
To plan for 720 good garments at 90% first-pass yield, how many must enter the line if repaired garments are excluded?
A 648 garments
B 800 garments
C 720 garments
D 792 garments
Answer: B. 800 garments. Divide required good output by the expected yield, 720/0.90.
Two seam sections require stitch counts of 96 and 144. Starting and ending backtacks add six stitches at each end of each section. What total stitch count should be budgeted?
A 264
B 252
C 288
D 246
Answer: A. 264. Base stitches total 240. Four ends add six each, adding 24 stitches.
Spreading a 150 m fabric batch wastes 6 m. Marker utilization is 84% of the remaining fabric. At constant width, what equivalent length is used by pattern pieces?
A 126.00 m
B 116.16 m
C 120.96 m
D 144.00 m
Answer: C. 120.96 m. Usable length is 144 m. At constant width, apply the 0.84 area fraction to that length.
On a seven-station line, total work per garment is 270 seconds and actual cycle time is 50 seconds. What is station balance efficiency?
A 90.0%
B 85.7%
C 77.1%
D 64.3%
Answer: C. 77.1%. Divide total work by 7 × 50 seconds, or 270/350.
Thirty 12-piece bundles each require one setup of 15 s and 25 s per garment. What total processing time is needed?
A 157.5 min
B 165.0 min
C 150.0 min
D 180.0 min
Answer: A. 157.5 min. Each bundle takes 15 + 12 × 25 = 315 s. Multiply by 30 and divide by 60.
Holding two days of cut work protects sewing from cutting stops but adds large queues. Which policy first tests whether less stock can support stable flow?
A Raise all queue limits
B Eliminate size identification
C Stop cutting until sewing ends
D Reduce buffer in measured steps
Answer: D. Reduce buffer in measured steps. Reducing the buffer gradually while tracking shortages tests how much stock is needed to absorb actual variation.
Shipment demand is 600 garments. The line produces 90 per hour for five hours and then 75 per hour. How many hours are needed in total?
A 7.0 h
B 6.5 h
C 8.0 h
D 7.5 h
Answer: A. 7.0 h. The first five hours yield 450. The remaining 150 take two hours at 75 per hour.